Optimal. Leaf size=199 \[ \frac{(a+b x)^{n+1} (c+d x)^{-n} \left (a^2 d^2 \left (n^2-3 n+2\right )+2 a b c d \left (1-n^2\right )+b^2 c^2 \left (n^2+3 n+2\right )\right ) \left (\frac{b (c+d x)}{b c-a d}\right )^n \, _2F_1\left (n,n+1;n+2;-\frac{d (a+b x)}{b c-a d}\right )}{6 b^3 d^2 (n+1)}-\frac{(a+b x)^{n+1} (c+d x)^{1-n} (a d (2-n)+b c (n+2))}{6 b^2 d^2}+\frac{x (a+b x)^{n+1} (c+d x)^{1-n}}{3 b d} \]
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Rubi [A] time = 0.144729, antiderivative size = 199, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {90, 80, 70, 69} \[ \frac{(a+b x)^{n+1} (c+d x)^{-n} \left (a^2 d^2 \left (n^2-3 n+2\right )+2 a b c d \left (1-n^2\right )+b^2 c^2 \left (n^2+3 n+2\right )\right ) \left (\frac{b (c+d x)}{b c-a d}\right )^n \, _2F_1\left (n,n+1;n+2;-\frac{d (a+b x)}{b c-a d}\right )}{6 b^3 d^2 (n+1)}-\frac{(a+b x)^{n+1} (c+d x)^{1-n} (a d (2-n)+b c (n+2))}{6 b^2 d^2}+\frac{x (a+b x)^{n+1} (c+d x)^{1-n}}{3 b d} \]
Antiderivative was successfully verified.
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Rule 90
Rule 80
Rule 70
Rule 69
Rubi steps
\begin{align*} \int x^2 (a+b x)^n (c+d x)^{-n} \, dx &=\frac{x (a+b x)^{1+n} (c+d x)^{1-n}}{3 b d}+\frac{\int (a+b x)^n (c+d x)^{-n} (-a c-(a d (2-n)+b c (2+n)) x) \, dx}{3 b d}\\ &=-\frac{(a d (2-n)+b c (2+n)) (a+b x)^{1+n} (c+d x)^{1-n}}{6 b^2 d^2}+\frac{x (a+b x)^{1+n} (c+d x)^{1-n}}{3 b d}+\frac{\left (2 a b c d \left (1-n^2\right )+a^2 d^2 \left (2-3 n+n^2\right )+b^2 c^2 \left (2+3 n+n^2\right )\right ) \int (a+b x)^n (c+d x)^{-n} \, dx}{6 b^2 d^2}\\ &=-\frac{(a d (2-n)+b c (2+n)) (a+b x)^{1+n} (c+d x)^{1-n}}{6 b^2 d^2}+\frac{x (a+b x)^{1+n} (c+d x)^{1-n}}{3 b d}+\frac{\left (\left (2 a b c d \left (1-n^2\right )+a^2 d^2 \left (2-3 n+n^2\right )+b^2 c^2 \left (2+3 n+n^2\right )\right ) (c+d x)^{-n} \left (\frac{b (c+d x)}{b c-a d}\right )^n\right ) \int (a+b x)^n \left (\frac{b c}{b c-a d}+\frac{b d x}{b c-a d}\right )^{-n} \, dx}{6 b^2 d^2}\\ &=-\frac{(a d (2-n)+b c (2+n)) (a+b x)^{1+n} (c+d x)^{1-n}}{6 b^2 d^2}+\frac{x (a+b x)^{1+n} (c+d x)^{1-n}}{3 b d}+\frac{\left (2 a b c d \left (1-n^2\right )+a^2 d^2 \left (2-3 n+n^2\right )+b^2 c^2 \left (2+3 n+n^2\right )\right ) (a+b x)^{1+n} (c+d x)^{-n} \left (\frac{b (c+d x)}{b c-a d}\right )^n \, _2F_1\left (n,1+n;2+n;-\frac{d (a+b x)}{b c-a d}\right )}{6 b^3 d^2 (1+n)}\\ \end{align*}
Mathematica [A] time = 0.131581, size = 154, normalized size = 0.77 \[ \frac{(a+b x)^{n+1} (c+d x)^{-n} \left (\frac{\left (a^2 d^2 \left (n^2-3 n+2\right )-2 a b c d \left (n^2-1\right )+b^2 c^2 \left (n^2+3 n+2\right )\right ) \left (\frac{b (c+d x)}{b c-a d}\right )^n \, _2F_1\left (n,n+1;n+2;\frac{d (a+b x)}{a d-b c}\right )}{n+1}+b (c+d x) (a d (n-2)-b c (n+2))+2 b^2 d x (c+d x)\right )}{6 b^3 d^2} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.061, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( bx+a \right ) ^{n}{x}^{2}}{ \left ( dx+c \right ) ^{n}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x + a\right )}^{n} x^{2}}{{\left (d x + c\right )}^{n}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (b x + a\right )}^{n} x^{2}}{{\left (d x + c\right )}^{n}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x + a\right )}^{n} x^{2}}{{\left (d x + c\right )}^{n}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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